On Jan 7, 2011, at 5:21 PM, Thibault Martin-Lagardette wrote:
I'd say something like:
a = NSNumber.numberWithDouble(0.0/0.0)
which returns the exact same thing as:
a = (0.0/0.0)
Does the resulting NaN automatically convert to NSNumber?
I need to pass the object initialized this way to a function in another framework, e.g.
[focusParameter setNumberValue:[NSNumber numberWithDouble:NAN]];
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