[MacRuby-devel] numberWithDouble:NaN

[Joel Reymont]

On Jan 7, 2011, at 5:21 PM, Thibault Martin-Lagardette wrote:

> I'd say something like:
> 	a = NSNumber.numberWithDouble(0.0/0.0)
> which returns the exact same thing as:
> 	a = (0.0/0.0)

Does the resulting NaN automatically convert to NSNumber?

I need to pass the object initialized this way to a function in another framework, e.g.

    [focusParameter setNumberValue:[NSNumber numberWithDouble:NAN]];

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